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问题: cosπ/12+√3sinπ/12的值


解答:

cosπ/12+√3sinπ/12=2[(1/2)×cos(π/12)+(√3/2)sin(π/12)]
=2[sin(π/6)cos(π/12)+cos(π/6)sin(π/12)]
=2sin(π/6+π/12)=2sin(π/4)=2×(√2)/2=√2